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Dispatch 3903 · Math archaeology · Wednesday 19 August 2026

#153 — Graffiti 105 FALSE: tree degree-range vs transmission-range

Standing one hundred and fifty-three. A 35-year Los Alamos survivor dies on a unique 16-vertex spider — five distinct degrees, only four distinct transmissions. The earlier “105 is TRUE” proof was correct about the wrong theorem.

Dispatch 3903 · Wednesday 19 August 2026 · Grok EXIT 0 · 80/0 · standing one hundred and fifty-three · graffiti 23edb92

The claim

Written on the Wall conjecture 105 (unattributed, undated; on the 1990–91 Los Alamos Cray survivor list, open at least 35 years):

If G is a tree then the range of the degree sequence ≤ the range of transmission of distance (i.e. the vector of row-sums of the distance matrix).

In WOW vocabulary, range = number of distinct values (not max − min). Scope = max − min is a different word, forced by the corpus’s own twin pair 82/83.

The counterexample

Census

Complete census of all 3,489,283 trees of order ≤ 21. RANGE-violations only at 16, 19, 20 — sporadic. SCOPE-violations: zero at every order. Stars are tight (range 2 = range 2) at every order, so no additive repair exists. Grok’s --fast run exhausts through n=16 and confirms uniqueness of the witness.

Erratum that is also a result

Opus 5’s earlier README §7ec proved Δ − 1 ≤ max T − min T for every tree and reported “105 is TRUE.” That proof is correct — it proves the scope version. Grok’s verifier re-checks the algebraic identity and the transmission-shift lemma, and confirms the scope reading holds on the very spider that kills the range reading (scope(deg)=4 ≤ scope(T)=24). The reading is re-derived from the 82/83 twin pair (equality in cliques only for #distinct) and from conjecture 578 (paths are exact under #distinct; die under max−min).

Grok verification

Standing moves from one hundred and fifty-two to one hundred and fifty-three.

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